If the quadratic equation px2-2√5px+15 0
Weblf the roots of px 2+2qx+r=0 and qx 2−2 prx+q=0 are simultaneously real, then A p=q ; r =0 B 2q= pr C pr=q 2 D pr=q Medium Solution Verified by Toppr Correct option is C) Since roots are real, ⇒(2q) 2−4pr≥0 and (2 pr) 2−4q 2≥0 4q 2≥4pr and 4pr≥4q 2 To hold above two equations simultenously ∴q 2=pr Solve any question of Quadratic Equations with:- WebIt is given that the quadratic equation `px^2-2sqrt5px+15=0` has two equal roots. ∴`D=0` ⇒`(-2sqrt5p)^2-4xxpxx15=0` ⇒`20p^2-60p=0` ⇒` 20p(p-3)=0` ⇒`p=0 or p-3=0` ⇒`p=0 or p=3` For `p=0`, we get `15=0` which is not true. ∴`p≠0` Hence, the value of p is 3.
If the quadratic equation px2-2√5px+15 0
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Web14 okt. 2024 · px² - px + 1 = 0 The quadratic equation has equal roots ⇒ The discriminant is equal to zero Find p: b² - 4ac = 0 Sub a = p , b = -p , c = 1 into the equation: (-p)² - 4 (p) (1) = 0 Evaluate each term: p² - 4p = 0 Take out common factor p: p ( p - 4) = 0 Apply zero product property: p = 4 or p = 0 (rejected as it will make the equation meaningless) WebFind the p and q such that px 2+5x+2=0 and 3x 2+10x+q=0 have both roots in common Medium Solution Verified by Toppr Given set of equation are px 2+5x+2=0 .......... (1) 3x 2+10x+q=0 ........ (2) As (1) & (2) are having same roots Sum of roots are equal (c/a) $$ \dfrac {2} {p}= \dfrac {2} {3}$$ $$\dfrac {2} {3/2}= \dfrac {2} {3}$$ ⇒q=4
Web24 mrt. 2024 · By equating it with the general quadratic equation we get a=p, b$ = - 2\sqrt 5 p$ and c=15. Now we will calculate its discriminant by formula ${b^2} - 4ac = 0$. \Rightarrow {\left( { - 2\sqrt 5 p} \right)^2} - 4 \times p \times 15 = 0 \\ WebClick here👆to get an answer to your question ️ Let alpha and beta be the roots of equation px^2 + qx + r = 0, p≠ 0 . If p, q, r are in A. P. and 1alpha + 1beta = 4 , then the value of alpha ... If a, b, c are distinct numbers in arithmetic progression and roots of the quadratic equation (a + 2 b ...
WebIf in equation ax2 +bx+c = 0 the two roots are equalThen b2 −4ac = 0In equation px2 −2 5px+15= 0a = p,b= −2 5p and c= 15Then b2 −4ac = 0⇒ (−2 5p)2 −4×p×15 = 0⇒ 20p2 …
WebTwo quadratic equations px2−2qx+p=0⋯(i) and qx2−2px+q =0⋯(ii) ∀ p,q∈R. If the roots of the equation (i) are real and unequal, then equation (ii) will have: Q. Consider two …
WebA quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax 2 + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term. The important condition for an equation to be a quadratic equation is the coefficient of x 2 is a non-zero term (a ≠ 0). For writing a … christmas light show in greensboro ncWebif the quadratic equation px2-2√5px +15=0 has two equal roots then find the value of p@ShikshaZone - YouTube #CreateWithCare @ShikshaZone @cbseclassvideos … christmas light show in greensboroWeb19 feb. 2024 · If the ratio of the roots of equation px2+qx+q=0 is a:b, prove that root a/b+root b/a+root q/p See answers Advertisement abhi178 Let α and β are the roots of given equation px² + qx + q = 0 sum of roots = α + β = -q/p -------- (1) product of roots = αβ = q/p ------- (2) Given, ratio of roots = a/b α/β = a/b -------- (3) christmas light show in gray tnWebQ1 If the quadratic equation px2 – 2√5px + 15 = 0 has equal roots, then find the value of p. 3,513 views Jan 1, 2024 67 Dislike Share Save GRAVITY COACHING CENTRE … christmas light show in grand rapids miWebBest answer It is given that the quadratic equation px2 - 2√5 px + 15 = 0 has two equal roots For p = 0, we get 15 = 0, which is not true. ∴ p ≠ 0 Hence, the value of p … christmas light show in gaWebSolution. The given quadratic equation is, px2−2√5px+15= 0. This is of the form ax2+bx+c =0. where, a= p,b =−2√5p,c= 15. We have, D=b2−4ac. = (−2√5p)2−4×p×15. = … christmas light show in el pasoWeb15 okt. 2024 · The roots of the quadratic equation: x = (-b ± √D)/2a, where D = b 2 – 4ac. 2. ... If the coefficient of x in the quadratic equation x 2 + bx + c =0 was taken as 17 in place of 13, its roots … christmas light show in griffith park